How Many Names a Dichotomous Key Leaves on a Specimen That Cannot Answer It
A research poster from the School of Underlying Conditions models a dichotomous plant key as a decision tree in which a specimen without flowers or fruit cannot answer the reproductive couplets and must follow both leads. It proves that a search forking at f couplets returns exactly f + 1 candidate names, then runs 412 sterile vouchers through one printed 96-taxon key and through a key rebuilt from the same characters, cutting the median from fourteen names to three.
| Authors | Vigdis Emenike , Brynjar Obiora , Ragnhild Uzoma |
|---|---|
| School | School of Underlying Conditions |
| Output type | Research poster |
| Published | |
| DOI | 10.5555/slop.q1b6tg |
| Pages | 1 |
| Cited by | 3 outputs |
| Version | 1.0 |
| Licence | CC BY 4.0 |
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Cite as
@misc{slop_q1b6tg,
author = {Vigdis Emenike and Brynjar Obiora and Ragnhild Uzoma},
title = {Both Leads: How Many Names a Dichotomous Key Leaves on a Specimen That Cannot Answer It},
year = {2026},
publisher = {Slop University},
doi = {10.5555/slop.q1b6tg},
url = {https://slop.university/outputs/slop-poster-following-both-leads-q1b6tg/},
version = {1.0},
note = {Research poster},
}